PHP Age Counting

age_counting.php

<?php

  // Your goal is to count how many items exist that have an age equal to or greater than 50, and print this final value.

  $ch = curl_init('https://coderbyte.com/api/challenges/json/age-counting');
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
  curl_setopt($ch, CURLOPT_HEADER, 0);
  $data = curl_exec($ch);
  curl_close($ch);

  $json_data = json_decode($data, true);
  $items = explode(', ', $json_data['data']);
  $count = array_reduce($items, function ($count, $item) {
    if (strpos($item, 'age=') !== false) {
      $age = explode('=', $item)[1];
      if ($age >= 50) return $count + 1;
    }
    return $count;
  }, 0);

  print_r($count); // 128

?>

I have tried this one to make it simple. But Lol it seems more complex but works as well.
In an interview, I couldn't answer this question answer as well but I think it's a very important and complex problem for newcomers.

<?php

  $ch = curl_init('https://coderbyte.com/api/challenges/json/age-counting');
  curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
  curl_setopt($ch, CURLOPT_HEADER, 0);
  $data = curl_exec($ch);
  curl_close($ch);

  $nedata = json_decode($data, true);

  preg_match_all('/age=(\d+)/', $nedata['data'], $matches);
  $count = 0;
  // $matches[0] contains the full match (e.g., "age=58").
  // $matches[1] = contains only the numbers, which is what you're after.
  foreach($matches[1] as $age)
      if($age >= 50)
          $count++;

  print_r($count);
?>