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@ShalokShalom
Created May 24, 2025 08:25
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To change `Value<'a>` to `Value<'v>` in the return type, you need to ensure that:
1. **The struct has a lifetime parameter `'v`**: The struct implementing this method must be defined with a lifetime `'v`, e.g., `struct MyStruct<'v> { ... }`.
2. **`'v` outlives `'a`**: The lifetime `'v` of the `Value`s must outlive the reference lifetime `'a` (i.e., `'v: 'a`). This ensures the `Value`s remain valid for the duration of the returned slice.
Here's the corrected signature if your struct is `MyStruct<'v>`:
```rust
impl<'v> MyStruct<'v> {
pub fn peek_frame<'a>(&'a self) -> Option<&'a [Value<'v>]>
where
'v: 'a, // Ensure 'v outlives 'a
{
// ... implementation ...
}
}
```
### Key Points:
- **Struct Lifetime**: The struct must carry the `'v` lifetime (e.g., `MyStruct<'v>`).
- **Lifetime Relationship**: Add `where 'v: 'a` to enforce that `'v` outlives the reference's lifetime `'a`.
- **Validity**: The `Value`s in the slice must be borrowed from data owned by the struct (with lifetime `'v`), not from the `&'a self` reference.
If these conditions aren’t met, the change will not compile.
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