Λύση άσκησης 13.6 απο το Βιβλίο "Η C++ σε βάθος" του Νίκου Μ. Χατζηγιαννάκη

gistfile1.txt

#include <iostream>
using namespace std;

class kafetiera{
	int kafes,gala,zaxari,nero,kafedes;
	bool ginetai(int z,int k,int n,int g);
	unsigned int what=0; // pernei times {1,2,3} , 1=sketos, 2=glykos, 3=metrios me gala.
	int x=-1; // apothikevei ton arithmo kafedwn (sketwn h glykwn h metriwn me gala) ths prohgoumenhs paraggelias.
	public:
		kafetiera();
		void status();
		void sketos(int ar);
		void glykos(int ar);
		void metrios_me_gala(int ar); // ar = arithmos kafedwn
		float cost(); // h methodos pou zhteitai sthn askhsh 13.6
};

bool kafetiera::ginetai(int z,int k,int n,int g){
	if(zaxari>=z && kafes>=k && nero>=n && gala>=g)
	return true;
	else
	return false;
}

kafetiera::kafetiera(){
	nero=1000;
	kafes=100;
	gala=300;
	zaxari=200;
	kafedes=0;
}

void kafetiera::status(){
	cout<<"Καφές:"<<kafes;
	cout<<" Γάλα:"<<gala;
	cout<<" Ζάχαρη:"<<zaxari;
	cout<<" Νερό:"<<nero<<endl;
	cout<<"Καφέδες μέχρι τώρα:"<<kafedes<<endl;
}

void kafetiera::sketos(int ar=1){
	if(!ginetai(0,2*ar,50*ar,0)){
		cout<<"Δέν υπάρχουν υλικά\n";
		return;
	}
	nero=nero-50*ar;
	kafes=kafes-2*ar;
	kafedes+=ar;
	if(ar>1){
		cout<<"Έτοιμοι οι "<<ar<<" σκέτοι......"<<endl;
	} else {
		cout<<"Έτοιμος ο σκέτος ......"<<endl;
	}
	what=1;
	x=ar;
}

void kafetiera::glykos(int ar=1){
	nero-=50*ar;
	kafes-=2*ar;
	zaxari-=2*ar;
	kafedes+=ar;
	if(ar>1){
		cout<<"Έτοιμοι οι "<<ar<<" γλυκοί......"<<endl;
	 } else {
		cout<<"Έτοιμος ο γλυκός ......"<<endl;
	}
	what=2;
	x=ar;
}

void kafetiera::metrios_me_gala(int ar=1){
	nero-=50*ar;
	kafes-=2*ar;
	zaxari-=1*ar;
	gala-=2*ar;
	kafedes+=ar;
	
	if(ar>1){
		cout<<"Έτοιμοι οι "<<ar<<" μέτριοι με γάλα......"<<endl;
	} else {
		cout<<"Έτοιμος ο μέτριος με γάλα......"<<endl;
	}
	what=3;
	x=ar;
}

float kafetiera::cost(){ // Ypologizei th xreosi ths teleutaias paraggelias
	if(what==0 || x==-1) cout<<"Δεν έχετε κάνει καμία παραγγελία μέχρι στιγμής..."<<endl;
	float xreosi;
	switch(what){
		case 1:
			xreosi=(0.01*50+0.05*2)*x;
			break;
		case 2:
			xreosi=(0.01*50+0.05*2+0.1*2)*x;
			break;
		case 3:
			xreosi=(0.01*50+0.05*2+0.1*1+0.2*2)*x;
			break;
	}
	return xreosi;
}

int main(){                 // Dokimazodas to programma:
	setlocale(LC_ALL,"greek");
	kafetiera filips;
	filips.status();
	cout<<"Cost="<<filips.cost()<<"$"<<endl;
	filips.sketos(1);
	cout<<"Cost="<<filips.cost()<<"$"<<endl;
	filips.glykos(4);
	cout<<"Cost="<<filips.cost()<<"$"<<endl;
	filips.metrios_me_gala(7);
	cout<<"Cost="<<filips.cost()<<"$"<<endl;
	filips.glykos(2);
	cout<<"Cost="<<filips.cost()<<"$"<<endl;
	filips.status();
}