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Kaprekar Constant
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#!/usr/bin/python | |
import sys | |
def kaprekar_diff(n): | |
nlist = list(str(n)) | |
if n < 1000: | |
if len(nlist) == 1: | |
nlist = nlist + list('000') | |
elif len(nlist) == 2: | |
nlist = nlist + list('00') | |
elif len(nlist) == 3: | |
nlist = nlist + list('0') | |
maxn = int(''.join(sorted(nlist, reverse=True))) | |
minn = int(''.join(sorted(nlist))) | |
return maxn - minn | |
def find_kaprekar(n1): | |
kpass = 1 | |
while kpass <= 7: | |
n1 = kaprekar_diff(n1) | |
if n1 == 6174: | |
break | |
else: | |
kpass += 1 | |
return kpass | |
# main | |
start,end = 1000,10000 | |
kaprekar_map = {} | |
for n in xrange(start,end): | |
if n not in [1111,2222,3333,4444,5555,6666,7777,8888,9999]: | |
kpass_out = find_kaprekar(n) | |
print 'n=' + str(n) + ' pass=' + str(kpass_out) | |
if kpass_out > 7: | |
continue | |
if kpass_out in kaprekar_map: | |
kaprekar_map[kpass_out].append(n) | |
else: | |
kaprekar_map[kpass_out] = [] | |
kaprekar_map[kpass_out].append(n) | |
print '** Kaprekar number analysis ' + str(start) + '-' + str(end-1) + ' **' | |
for key in kaprekar_map.keys(): | |
print 'Bucket:' + str(key) + ', Numbers which require ' + str(key)+ ' iterations=>'+ str(len(kaprekar_map[key])) |
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