version comparison

/*
Please implement a function that compares two version numbers version1 and version2.

If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

More examples:
1 < 2
1.1 < 1.1.2
1.0.0.0 = 1.0
2.0 < 10.0

Javascript template:
/**
 * @param {string} version1
 * @param {string} version2
 * @return {number}
 */
var compareVersion = function(version1, version2) {
    const arr1 = version1.split('.');
    const arr2 = version2.split('.');
    const maxLevels = Math.max(arr1.length, arr2.length);
    for (let i = 0; i < maxLevels; i++) {
      // if we're past the end of an array, normalize to 0 for comparison
      const versionOneLevel = i >= arr1.length ? 0 : parseInt(arr1[i], 10);
      const versionTwoLevel = i >= arr2.length ? 0 : parseInt(arr2[i], 10);
      if (versionOneLevel > versionTwoLevel) return 1;
      if (versionOneLevel < versionTwoLevel) return -1;
    }
    return 0;
};

console.log(compareVersion('1.0.1', '1'));
console.log(compareVersion('0.1', '13.37'));
console.log(compareVersion('1', '2'));
console.log(compareVersion('1.1', '1.1.2'));
console.log(compareVersion('1.0.0.0', '1.0'));
console.log(compareVersion('2.0', '10.0'));