Steps for a function

Building a Function:  An accumulator pattern refers to a function that follow these steps:

1. Identify the inputs.
      1a. Array: [], string "", object: {}, number:  0, bollean: true/false

2. Write a function definition with those inputs.
      2a. define parameters () 
      2b. function call/invoking:  function(arguments)

3. Identify the output, define the result variable, and return it.
      3a. Declare output type:  result; default ,  result = [] array, result = {} object, result = 0 num result = "" string
      3b. return statement - return result (one picked from above)
4. Determine how to iterate.
      4a. Which loop - for, while, while/do, for -in (Objects) 

5. Changes the data somehow.  This is the trickey part
      5a.  Do you need conditionals(if/elseif/else) -  comparisions
      5b.  Modelo %:  Do we need even/odd/remainder -  even (num % 2 === 0) , odd(num %2 !== 0)
      5b.  Add:  result += (array[i]) (num)  (string[i]) - also consider *=  /=
      5c.  Array:  result.push(array[i]) - also consider slice  
      5d.  Object:  result[object[key] = [i]
      5e.  String: result = result + items[i]  concatenation
      
    



// 16. Write a conditional statement to find the largest of the numbers in the array provided.


var num = [-5, -2, -6, 0, -1];
var largestNum = num[0];

for (var i = 1; i < num.length; i++) {

  if (num[i] > largestNum) {

    largestNum = num[i];

  }

}


// 9. FIZZ BUZZ
// Write a program that uses console.log to print each number up to 100, with a couple exceptions...
// If the number is divisible by 3, print "Fizz" instead of the number.
// If the number is divisible by 5, print "Buzz" instead of the number.
// If the number is divisible by both 3 and 5, print "FizzBuzz" instead of the number.

for (var i = 0; i < 100; i++) {

  if (i % 3 === 0 && i % 5 === 0) {

    console.log("FizzBuzz");

    document.getElementById("q9").innerHTML += "<p>FizzBuzz</p>";

  } else if (i % 3 === 0 && !(i % 5 === 0)) {

    console.log("Fizz");

    document.getElementById("q9").innerHTML += "<p>Fizz</p>";

  } else if (i % 5 === 0 && !(i % 3 === 0)) {

    console.log("Buzz");

    document.getElementById("q9").innerHTML += "<p>Buzz</p>";

  } else {

    console.log(i);

    document.getElementById("q9").innerHTML += "<p>" + i + "</p>";

  }


// HEADS OR TAILS?
// 17. Use the following variable for your coin flip action:

var coin = Math.floor(Math.random() * 2);

if (coin === 0) {

  var result = "heads";

} else {

  var result = "tails";

}

console.log(result);

document.getElementById("q17").innerHTML += "<p>" + result + "</p>";


// 5. You use Amazon Subscribe & Save to have six cans of cashews automatically sent to you each month.
//    Write a function that takes the price per unit and calculates the total for you each month.
//    Since the price of the cashews can change anytime, pass that amount into the function to get your total price.

function totalCost(price, amount) {

  return (price * amount);

}

totalCost(input1, input2));


// 1. Without using Math.min(), write a function called minimum(),
//    that takes two numbers from a user,
//    and outputs the smaller number into the HTML page.


function minimum (num1, num2) {

  if (num1 === num2) {

    return("same number");

  } else if (num1 < num2) {

    return(num1);

  } else if (num1 > num2) {

    return(num2);

  } else {

    return("incorrect input");

  }

}



var exampleArray = [1, 2, 3, 4];

function sum(array) {

  var result = 0;

  for (var i = 0; i < array.length; i++) {

    result += array[i];

  }

  return result;

}


/ 8. Write a function countBs() that takes a string as its only argument and returns
//    a number that indicates how many uppercase “B” characters are in the string.
//    HINT: Google charAt()

function countBs(string) {

  var count = 0;

  for (var i = 0; i < string.length; i++) {

    if (string.charAt(i) === "B");

      count++;

  }

  return count;

}