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Groovy List Destructuring
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| def (a,b,rest) = [0, 1, 2..-1].collect { [1,2,3,4][it] } | |
| assert a == 1 | |
| assert b == 2 | |
| assert rest == [3,4] |
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| List.metaClass.destructure = { ...n-> | |
| n.collect { delegate[it]} | |
| } | |
| def (a,b,rest) = [1,2,3,4].destructure(0, 1, 2..-1) | |
| assert a == 1 | |
| assert b == 2 | |
| assert rest == [3,4] |
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| def destructure(list,...n) { | |
| n.collect {list[it]} | |
| } | |
| def (a,b,rest) = destructure([1,2,3,4],0, 1, 2..-1) | |
| assert a == 1 | |
| assert b == 2 | |
| assert rest == [3,4] |
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