inplace function in zsh

inplace

#!/usr/bin/env zsh

inplace() {
     COMMAND="$1"
     FILEPATH="$2"
     set -x
     OUTPUT="$(bash -c "${COMMAND} '${FILEPATH}'")"
     RET=$?
     if [ $RET -eq 0 ]; then
         echo -n "$OUTPUT" >! "${FILEPATH}"
     else
         echo -n "$OUTPUT"
         return $RET
     fi
}

if i'm to prettify all the xml documents in current directory, imma run this command:

for filepath in "${(@f)$(find . -not -regex '\./\.git/.*' -type f)}"; do inplace 'xmllint --pretty 1' "$filepath"; done