My Solution To The Lonely Interger Problem in JavaScript

lonelyInt.js

/*
 * Complete the 'lonelyinteger' function below.
 *
 * The function is expected to return an INTEGER.
 * The function accepts INTEGER_ARRAY a as parameter.
 */

function lonelyinteger(a) {
  // If a is only 1 int long just return it
   if(a.length == 1) {
      return a;
  } else {
      // outer for loop to check values with
      outer: for( let i=0; i<a.length; i++) {
          // inner for loop to check values with
          inner: for (let j=0; j<a.length; j++) {
              if(i===j) {
                  continue inner;
              } else {
                  if( a[i] === a[j]) {
                      continue outer;
                  }
              }
          }
          return a[i];        
      }
  }


}