Created
March 14, 2012 02:18
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FizzBuzz One-Liner by CoffeeScript (without "if-else" statement)
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| fizzbuzz = (x) -> console.log (i % 3 is 0 and i % 5 is 0 and "fizzbuzz" or i % 3 is 0 and "fizz" or i % 5 is 0 and "buzz" or i) for i in [1..x] |
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